# Suppose that you have been hired to estimate the percentage Suppose that you have been hired to…

Suppose that you have been hired to estimate the percentage

Suppose that you have been hired to estimate the percentage of adults in your state who are literate. You take a random sample of 100 adults and find that 96 are literate. You then obtain a 95% confidence interval of 0.96 ± 1.96 · √(0.96)(0.04)/100, or 0.922 to 0.998. From it you conclude that you can be 95% confident that the percentage of all adults in your state who are literate is somewhere between 92.2% and 99.8%. Is anything wrong with this reasoning?Suppose that you have been hired to estimate the percentage

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